Question
Draw a line segment AB = 8 cm. Mark a point P in AB so that AP = 5 cm. At P, construct angle APQ = 30°.
✓
Answer
Steps of Construction:
(i) Draw a line segment $A B=8 cm$.
(ii) Mark a point $P$ in $A B$ such that $A P=5 cm$.
(iii) With centre $P$ and some suitable radius, draw an arc meeting $A B$ in L.
(iv) With centre $L$ and same radius cut arc LM.
(v) Bisect arc LM at $N$.
(vi) Join $PN$ and produce it to $Q$.
Then $\angle A P Q=30^{\circ}$
(i) Draw a line segment $A B=8 cm$.
(ii) Mark a point $P$ in $A B$ such that $A P=5 cm$.
(iii) With centre $P$ and some suitable radius, draw an arc meeting $A B$ in L.
(iv) With centre $L$ and same radius cut arc LM.
(v) Bisect arc LM at $N$.
(vi) Join $PN$ and produce it to $Q$.
Then $\angle A P Q=30^{\circ}$
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