Question
Draw a quadrilateral in the Cartesian plane, whose vertices are (-4, 5), (0, 7), (5, -5) and (-4, -2) also find its area.
✓
Answer
Area of quadrilateral ABCD = area of $\Delta BCE$ + area of trap. ABED
$ = \frac{1}{2} \times 10.4 \times 5 + \frac{1}{2}(10.4 + 7) \times 4$
$ = 5.2 \times 5 + 2 \times 17.4$
= 26 + 34.8 = 60.8 sq. units.
$ = \frac{1}{2} \times 10.4 \times 5 + \frac{1}{2}(10.4 + 7) \times 4$
$ = 5.2 \times 5 + 2 \times 17.4$
= 26 + 34.8 = 60.8 sq. units.
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