Question
Draw a trapezium ABCD in which AB || DC, AB = 7cm, BC = 5cm, AD = 6.5cm and $\angle\text{B}=60^\circ.$

Answer


Steps of construction:
Step 1: Draw AB equal to 7cm.
Step 2: Make an angle, $\angle\text{ABX},$ equal to 60°.
Step 3: With B as the centre, draw an arc of 5cm. Name that point as C. Join B and C.
Step 4: AB || DC
$\therefore\angle\text{ABX}+\angle\text{BCY}=180^\circ$
$\Rightarrow\angle\text{BCY}=180^\circ-60^\circ=120^\circ$
Draw an angle, $\angle\text{BCY},$ equal to 120º.
Step 5: With A as the centre, draw an arc of length 6.5cm, which cuts CY. Mark that point as D.
Step 6: Join A and D.
​Thus, ABCD is the required trapezium.

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