Question
Draw a triangle ABC in which BC = 4cm, AB = 3cm and $\angle\text{B}=45^\circ.$ Also, draw a perpendicular from A on BC.

Answer


Steps of construction:
Step I: Draw a line segment AB of length 3cm.
Step II: Draw an angle of 45° and cut an arc at this angle at a radius of 4cm at C.
Step III: Join AC to get the required triangle.
Step IV: With A as centre, draw intersecting arcs at M and N.
Step V: With centre M and radius more than half of MN, cut an arc on the opposite side of A.
Step VI: With N as centre and radius the same as in the previous step, cut an arc intersecting the previous arc at E.
Step VII: Join AE, it meets BC at D, then AE is the required perpendicular.

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