Question
Draw $\triangle\text{PQR}$ in which $\angle\text{Q}=80^\circ,$ $\angle\text{R}=55^\circ$ and $QR = 4.5\ cm$. Draw the perpendicular bisector of side $QR$.
✓
Answer
Steps of construction:
Step I: Draw a line segment $QR = 4.5\ cm.$
Step II: Draw $\angle\text{RQX}=80^\circ$ and $\angle\text{QRY}=55^\circ.$
Step III: Let $QX$ and $RY$ intersect at $P$ so that $PQR$ is the required triangle.
Step IV: With $Q$ as centre and radius more that $2.25\ cm$, draw arcs on either sides of $QR$.
Step V: With $R$ as centre and radius more than $2.25\ cm$, draw arcs intersecting the previous arcs at $M$ and $N$.
Step VI: Join $MN$ is the required perpendicular bisector of $QR$.
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