MCQ
During which time interval is the particle described by these position graphs at rest?
  • A
    $0 -1\ s$
  • B
    $1 -2\ s$
  • $2 -3\ s$
  • D
    $3 -4\ s$

Answer

Correct option: C.
$2 -3\ s$
c
Between $2 -3sec$ both $x$ and $y$ position are not changing.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

When 1m, 1kg and 1 min are taken as the fundamental units, the magnitude of the force is 36 units. What will be the value of this force in CGS system?
A particle moves in the $xy$ plane with a constant acceleration $'g'$ in the negative $y$-direction. Its equation of motion is $y = ax-bx^2$, where $a$ and $b$ are constants. Which of the following are correct?
A sphere is rolling without slipping on a fixed horizontal plane surface. In the figure $A$ is the point of contact, $B$ is the centre of sphere and $C$ is its topmost point, then

$(i){\vec V_C} - {\vec V_A} = 2\left( {{{\vec V}_B} - {{\vec V}_C}} \right)$

$(ii){\vec V_C} - {\vec V_B} = {\vec V_B} - {\vec V_A}$

$(iii)\left| {{{\vec V}_C} - {{\vec V}_A}} \right| = 2\left| {{{\vec V}_B} - {{\vec V}_C}} \right|$

$(iv)\left| {{{\vec V}_C} - {{\vec V}_A}} \right| = 4\left| {{{\vec V}_B}} \right|$

Two particles of masses $M$ and $4M$ are released from a distance $10\,metres$ from each other. Find the point of collision from smaller particle .............. $\mathrm{metres}$
A body is moving along a circular path. How much work is done by the centripetal force?
Time period of a simple pendulum is $T$. The time taken to complete $5 / 8$ oscillations starting from mean position is $\frac{\alpha}{\beta} T$. The value of $\alpha$ is ..... .
A carnot engine whose sink is at 300K has an efficiency of 40%. By how much should the temperature of source be increased so as to increase its efficiency by 50% of original efficiency.
There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is $T$. If the resultant acceleration becomes $g/4,$ then the new time period of the pendulum is
The period of a simple pendulum is doubled, when
Time taken to heat water upto a temperature of 40°C (from room temperature) is t1 and time taken to heat mustard oil (of same mass and at room temperature) upto a temperature of 40°C is t2, then (given mustard oil has smaller heat capacity).