MCQ
Each question consists of two statements, namely, Assertion (A) and Reason (R). For selecting the correct answer: use the following code:
Assertion (A) Reason (R)
If the median and mode of a frequency distribution are 150 and 154 respectively, then its mean is 148. Mean, median and mode of a frequency distribution are related as: mode = 3median - 2mean
  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).
  • B
    Both Assertion (A) and Reason (R) are true but Reason (R) is a not a correct explanation of Assertion (A).
  • C
    Assertion (A) is true and Reason (R) is false.
  • D
    Assertion (A) is false and Reason (R) is true.

Answer

Correct option: A.
Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).
Reason (R) is true.
Using the relation given in (R), we have
Median = 150
Mode = 154
Mode = 3Median - 2Meen
Hence, mean $=\frac{3\text{Median}-\text{Mode}}{2}=\frac{3(150)-154}{2}=\frac{450-154}{2}=\frac{296}{2}=148$
Thus, Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

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