Question
Elements of atomic number $6$ is placed in
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$2N{O_2}\left( g \right) \rightleftharpoons {N_2}{O_4}\left( g \right)$ is
$\left( {R = \frac{{25}}{3}J/K.mol,\ln 2 = 0.7,\ln 3 = 1.1} \right)$
$(I)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,}
\end{array}$
$(II)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$(III)$ $\begin{array}{*{20}{c}}
\,\,{C{H_3}} \\
{|\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - COOH} \\
{|\,\,\,\,\,\,} \\
\,\,{C{H_3}\,}
\end{array}$
$(IV)$ $(CH_3-CH_2)_3C-COOH$
$A^+/A = \,-\,2.93\, Volt$, $B^+/B = 0.80\,V$
$C^{+2}/C = \,-\,2.37\, Volt$, $D^{+3}/D = \,-\,0.74\,V$
Increasing order of reducing power of these metals