EN of element A is E_1 and IP is E_2 hence EA will be - Vidyadip

Question

$EN$ of element $A$ is $E_1$ and $IP$ is $E_2$ hence $EA$ will be

✓

Answer

a
$\frac{\mathbb{P}+\mathrm{EA}}{2}=\mathrm{EN} ; \frac{\mathrm{E}_{2}+\mathrm{EA}}{2}=\mathrm{E}_{1}$

hence $\mathrm{EA}=2 \mathrm{E}_{1}-\mathrm{E}_{2}$

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