MCQ
$EN$ of element $A$ is $E_1$ and $IP$ is $E_2$ hence $EA$ will be
- ✓$2E_1 -E_2$
- B$E_1 -E_2$
- C$E_1 -2E_2$
- D$(E_1 + E_2)/2$
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(Given : $\left.pK _{ a }\left( CH _{3} COOH \right)=4.76\right)$
$\log 2=0.30$ $\log 3=0.48$ $\log 5=0.69$ $\log 7=0.84$ $\log 11=1.04$
$(A)$ $(a)$ $n=3,1=1, m_{l}=1, m_{s}=+\frac{1}{2}$
$\quad (b)$ $n =3,1=2, m _{l}=1, m _{s}=+\frac{1}{2}$
$(B)$ $(a)$ $n =3,1=2, m _{l}=-2, m _{s}=-\frac{1}{2}$
$\quad (b)$ $n =3,1=2, m _{l}=-1, m _{s}=-\frac{1}{2}$
$(C)$ $(a)$ $n=4,1=2, m_{l}=2, m_{s}=+\frac{1}{2}$
$\quad (b)$ $n =3,1=2, m _{l}=2, m _{s}=+\frac{1}{2}$
The pairs of electron present in degenerate orbitals is/are...... .