MCQ
Energy of electron of hydrogen atom in second Bohr orbit is
  • $ - 5.44 \times {10^{ - 19}}J$
  • B
    $ - 5.44 \times {10^{ - 19}}\,kJ$
  • C
    $ - 5.44 \times {10^{ - 19}}\,cal$
  • D
    $ - 5.44 \times {10^{ - 19}}\,eV$

Answer

Correct option: A.
$ - 5.44 \times {10^{ - 19}}J$
a
(a) $E = - \frac{{2.172 \times {{10}^{ - 18}}}}{{{n^2}}} = \frac{{ - 2.172 \times {{10}^{ - 18}}}}{{{2^2}}}$

        $ = - 5.42 \times {10^{ - 19}}J$.

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