Question
Equal torqueses are applied on a cylinder and a sphere. Both have same mass and radius. The cylinder rotates about its axis and the sphere rotates about one of its diameters. Which will acquire greater speed? Explain why.

Answer

We know, $\tau=\text{l}\alpha\text{ or }\alpha=\frac{\tau}{\text{l}}$ 
$\therefore$ Angular acceleration produced in the rylinder is $\alpha_\text{c}=\frac{\tau}{\text{I}_\text{c}}$
Similarly, acceleration produced in the sphere is
$\alpha_\text{s}=\frac{\tau}{\text{I}_\text{s}}$
$\therefore\frac{\alpha_\text{c}}{\alpha_\text{s}}=\frac{\text{I}_\text{s}}{\text{I}_\text{c}}$
Now $\text{I}_\text{s}=\frac{2}{3}\text{MR}^2$ and $\text{I}_\text{}C=\frac{1}{2}\text{MR}^2$
$\therefore\frac{\alpha_\text{c}}{\alpha_\text{s}}=\frac{4}{3}$
or $\alpha_\text{c}=\frac{4}{3}\alpha_\text{s}\text{ and }\alpha_\text{c}>\alpha_\text{s}.$
Thus cylinder will acquire greater speed than that of the sphere.

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