Equations x + y = 2, , ,2x + 2y = 3will have - Vidyadip

MCQ

Equations $x + y = 2,\,\,2x + 2y = 3$will have

A
Only one solution
B
Many finite solutions
✓
No solution
D
None of these

✓

Answer

Correct option: C.

No solution

c
(c) Form $(ii)$ equation, $2(x + y) = 3$ or $2.2 = 3$ or $4=3$
Which is not feasible, so given equation has no solution.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 3 and 4 . determinant and metrices→3 and 4 . determinant and metrices — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

For the area bounded by the curve y = ax, the line x = 2 and x - axis to be 2 sq. units, the value of a must be equal to:

2
4
6
8

A line $'l'$ passing through origin is perpendicular to the lines $l_{1}: \overrightarrow{ r }=(3+ t ) \hat{ i }+(-1+2 t ) \hat{ j }+(4+2 t ) \hat{ k }$ ; $l_{2}: \overrightarrow{ r }=(3+2 s ) \hat{ i }+(3+2 s ) \hat{ j }+(2+ s ) \hat{ k }$ . If the co-ordinates of the point in the first octant on ${ }^{\prime} l_{2}^{\prime}$ at a distance of $\sqrt{17}$ from the point of intersection of $^{\prime} l^{\prime}$ and ${ }^{\prime} l_{1}^{\prime}$ are $( a , b , c ),$ then $18( a+ b + c )$ is equal to ........ .

The length of the perpendicular drawn from the point $(5, 4, -1)$ on the line $\frac{{x - 1}}{2} = \frac{y}{9} = \frac{z}{5}$ is

Consider the system of linear equations

$-x+y+2 z=0$

$3 x-a y+5 z=1$

$2 x-2 y-a z=7$

Let $S_{1}$ be the set of all $\mathrm{a} \in {R}$ for which the system is inconsistent and $S_{2}$ be the set of all $a \in {R}$ for which the system has infinitely many solutions. If $n\left(S_{1}\right)$ and $n\left(S_{2}\right)$ denote the number of elements in $S_{1}$ and $\mathrm{S}_{2}$ respectively, then

A function $f,$ defined for all positive real numbers, satisfies the equation $f(x^2) = x^3$ for every $x > 0$ . Then the value of $f ‘ (4) =$

$\int\text{e}^{\text{x}}\Big(\frac{1-\sin\text{x}}{1-\cos\text{x}}\Big)\text{dx}=$

$-\text{e}^{\text{x}}\tan\frac{\text{x}}{2}+\text{C}$
$-\text{e}^{\text{x}}\cot\frac{\text{x}}{2}+\text{C}$
$-\frac{1}{2}\text{e}^{\text{x}}\tan\frac{\text{x}}{2}+\text{C}$
$-\frac{1}{2}\text{e}^{\text{x}}\cot\frac{\text{x}}{2}+\text{C}$

If A is a matrix of order m×n and B is a matrix such that AB^T and B^TA are both defined, then the order of matrix B is:

m×n
n×n
n×m
m×n

Three digit numbers $x17, 3y6$ and $12z$ where $x, y, z$ are integers from $0$ to $9$, are divisible by a fixed constant $k$. Then the determinant $\left| {\,\begin{array}{*{20}{c}}x&3&1\\7&6&z\\1&y&2\end{array}\,} \right|$ + $48$ must be divisible by

Domain of the definition of function

$f(x) = \sqrt {\frac{{4 - {x^2}}}{{\left[ x \right] + 2}}} $ is $($ where $[.] \rightarrow G.I.F.)$

For the curve $\sqrt{\text{x}}+\sqrt{\text{y}}=1,\frac{\text{dy}}{\text{dx}}$ at $\Big(\frac{1}{4},\frac{1}{4}\Big)$ is:

$\frac{1}{2}$
1
-1
0