- AHydration of ethylene
- BFermentation of sugars
- ✓Both the above
- DNone of these
$C{H_2} = C{H_2} + \mathop {{\text{ }}H}\limits^ + S{\mathop O\limits^ - _4} \to C{H_3} - C{H_2} - HS{O_4}$
$C{H_3} - C{H_2}HS{O_4}\mathop {\xrightarrow{{{H_2}O}}}\limits_{Boil} C{H_3} - C{H_2} - OH + {H_2}S{O_4}$
Fermentation of sugars:
${C_{12}}{H_{22}}{O_{11}} + {H_2}O\xrightarrow{{{\text{Invertase}}}}\mathop {{C_6}{H_{12}}{O_6}}\limits_{{\text{Glucose}}} + \mathop {{C_6}{H_{12}}{O_6}}\limits_{{\text{Fructose}}} $
$\mathop {{C_6}{H_{12}}{O_6}}\limits_{{\text{Glucose}}\,\,{\text{or}}\,{\text{Fructose}}} \xrightarrow{{{\text{Zymase}}}}\,2{C_2}{H_5}OH + 2C{O_2}$
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$\begin{array}{*{20}{c}} A \\ {{\text{(simplest optically active alkene)}}} \end{array}\,\xrightarrow[{(ii)\,{X_2}/\Delta }]{{(i)\,{H_2}/Ni/\Delta }}$
Statement $(I)$ : Fusion of $\mathrm{MnO}_2$ with $\mathrm{KOH}$ and an oxidising agent gives dark green $\mathrm{K}_2 \mathrm{MnO}_4$.
Statement $(II)$ : Manganate ion on electrolytic oxidation in alkaline medium gives permanganate ion.
In the light of the above statements, choose the correct answer from the options given below.
$\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^1}} \right);\,\,R\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^2}} \right)$The formula of ionic compounds that can be formed between these elements are
