MCQ
Ethanol is prepared industrially by
  • A
    Hydration of ethylene
  • B
    Fermentation of sugars
  • Both the above
  • D
    None of these

Answer

Correct option: C.
Both the above
c
(c) Hydration of alkenes

$C{H_2} = C{H_2} + \mathop {{\text{ }}H}\limits^ +  S{\mathop O\limits^ -  _4} \to C{H_3} - C{H_2} - HS{O_4}$

$C{H_3} - C{H_2}HS{O_4}\mathop {\xrightarrow{{{H_2}O}}}\limits_{Boil} C{H_3} - C{H_2} - OH + {H_2}S{O_4}$

Fermentation of sugars:

${C_{12}}{H_{22}}{O_{11}} + {H_2}O\xrightarrow{{{\text{Invertase}}}}\mathop {{C_6}{H_{12}}{O_6}}\limits_{{\text{Glucose}}}  + \mathop {{C_6}{H_{12}}{O_6}}\limits_{{\text{Fructose}}} $

$\mathop {{C_6}{H_{12}}{O_6}}\limits_{{\text{Glucose}}\,\,{\text{or}}\,{\text{Fructose}}} \xrightarrow{{{\text{Zymase}}}}\,2{C_2}{H_5}OH + 2C{O_2}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Which of the following is the correct reducing order of bond-angle
Which of the following substances when dissolved in water will give a solution that does not conduct electricity
The total number of monohalogenated organic products in the following (including stereoisomers) reaction is.........

$\begin{array}{*{20}{c}} A \\ {{\text{(simplest optically active alkene)}}} \end{array}\,\xrightarrow[{(ii)\,{X_2}/\Delta }]{{(i)\,{H_2}/Ni/\Delta }}$

Hydroboration of $1$- methylcyclopentene using $B_2D_6$ , followed by  treatment with alkaline hydrogen peroxide, gives
Which one of the following halogen compounds is not useful as substrate in ${{S}_{{{N}^{2}}}}$ reaction.
Given below are two statements:

Statement $(I)$ : Fusion of $\mathrm{MnO}_2$ with $\mathrm{KOH}$ and an oxidising agent gives dark green $\mathrm{K}_2 \mathrm{MnO}_4$.

Statement $(II)$ : Manganate ion on electrolytic oxidation in alkaline medium gives permanganate ion.

In the light of the above statements, choose the correct answer from the options given below.

$\begin{matrix}
   \,\,\,C{{H}_{3}}  \\
   \,\,\,|\,\,\,  \\
   C{{H}_{3}}-CH\xrightarrow{KMn{{O}_{4}}}  \\
   \,\,\,|\,\,\,  \\
   \,\,\,C{{H}_{3}}  \\
\end{matrix}(A)\xrightarrow[\Delta ]{{{H}^{+}}}(B)\xrightarrow[ROOR]{HBr}(C)$ Product $(C)$ in the above reactions is
The electronic configuration of four elements $L, P, Q$ and $R$ are given in brackets $L\,\left( {1{s^2},\,\,2{s^2}\,2{p^4}} \right);\,\,Q\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^2}\,\,3{p^5}} \right)$;$P$

$\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^1}} \right);\,\,R\,\left( {1{s^2},\,\,2{s^2}\,2{p^6},\,\,3{s^2}} \right)$The formula of ionic compounds that can be formed between these elements are

The aldehydes which will not form Grignard product with one equivalent Grignard reagents are
The maximum number of electrons present in an orbit $l = 3$, is