- AAcetic acid
- ✓Sodium metal
- CHydrogen iodide
- DAcidic potassium dichromate
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$Pt ( s )\left| H _2( s )( latm )\right| H ^{+}\left( aq ,\left[ H ^{+}\right]=1\right)|| Fe ^{3+}( aq ), Fe ^{2+}( aq ) \mid \operatorname{Pt}( s )$
Given : $E _{ Fe ^{3+} / e ^{2 *}}^0=0.771\,V$ and $E _{ H ^{+}+\frac{1}{2} H _2}^0=0 V , T =298\,K$
If the potential of the cell is $0.712\,V$ the ratio of concentration of $Fe ^{2+}$ to $Fe ^{2+}$ is $........$.(Nearest integer)
$\mathop {C{H_2} = CH - Br}\limits_{(I)} $ $\mathop {{\text{C}}{{\text{H}}_3} - Br}\limits_{\left( {II} \right)} $ $\mathop {\begin{array}{*{20}{c}}
{C{H_3} - CH - Br} \\
{|\,\,} \\
{\,\,\,C{H_3}}
\end{array}}\limits_{\left( {III} \right)} $ $\mathop {C{H_3}C{H_2}Br}\limits_{\left( {IV} \right)} $