MCQ
Ethyl benzoate reacts with $PC{l_5}$ to give
- A${C_2}{H_5}Cl + {C_6}{H_5}COCl + POC{l_3} + HCl$
- ✓${C_2}{H_5}Cl + {C_6}{H_5}COCl + POC{l_3}$
- C$C{H_3}COCl + {C_6}{H_5}COCl + POC{l_3}$
- D${C_2}{H_5}Cl + {C_6}{H_5}COOH + POC{l_3}$
✓
Answer
Correct option: B.
${C_2}{H_5}Cl + {C_6}{H_5}COCl + POC{l_3}$
b
Ethyl benzoate reacts with $PCl _5$ to give $C _2 H _5 Cl + C _6 H _5 COCl + POCl _3$
Ethyl benzoate reacts with $PCl _5$ to give $C _2 H _5 Cl + C _6 H _5 COCl + POCl _3$
$C _6 H _5 COOCH _2 CH _3+ PCl _5 \rightarrow \underset{\text { Ethyl chloride }}{ C _2 H _5 Cl }+\underset{\text { benzoyl chloride }}{ C _6 H _5 COCl }+\underset{\text { phosphorous oxy chloride }}{ POCl _3}$
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{||}\\
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