MCQ
Ethyl bromide reacts with lead-sodium alloy to form
- ✓Tetraethyl lead
- BTetraethyl bromide
- CBoth $(a)$ and $(b)$
- DNone of the above
✓
Answer
Correct option: A.
Tetraethyl lead
a
(a) $4{C_2}{H_5}Br + 4Pb/Na \to \mathop {{{({C_2}{H_5})}_4}Pb}\limits_{\scriptstyle{\rm{Tetra}}\,\,{\rm{Ethyl}}\,\,{\rm{lead}}\,\atop\scriptstyle\,({\rm{TEL}})} + 4NaBr$
(a) $4{C_2}{H_5}Br + 4Pb/Na \to \mathop {{{({C_2}{H_5})}_4}Pb}\limits_{\scriptstyle{\rm{Tetra}}\,\,{\rm{Ethyl}}\,\,{\rm{lead}}\,\atop\scriptstyle\,({\rm{TEL}})} + 4NaBr$
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