MCQ
Ethylene reacts with ozone to give
  • Formaldehyde
  • B
    Ethyl alcohol
  • C
    Ozonide
  • D
    Acetaldehyde

Answer

Correct option: A.
Formaldehyde
a
(a) $C{H_2} = C{H_2}\mathop {\xrightarrow{{1\,)\,{O_3}}}}\limits_{2\,)\,Zn/{H_2}O} \mathop {HCHO + HCHO}\limits_{{\text{Formaldehyde}}} $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Ethyl acetoacetate shows, which type of isomerism
Anomalous behaviour of oxygen is due to its
The reaction $C{H_2} = CH - C{H_3} + HBr \to C{H_3}CHBr - C{H_3}$ is
Given
$
\begin{array}{l}
C_{\text {graphite }}+O_2 \rightarrow CO_2(g): \\
\Delta_{r} H^0=-393.5 KJ / mol
\end{array}
$
$
H_2(g)+\frac{1}{2} O_2(g) \rightarrow H_2 O(l)
$
$
\Delta_r H^0=-285.8 kJ / mol
$
$
CO_2(g)+2 H_2 O(l) \rightarrow CH_4(g)+2 O_2(g):
$
$
\Delta_r H^0=+890.3 kJ mol^{-1}
$
Based on the above thermochemical equations, the value of $\Delta_r H^0$ at 298 K for the reaction
$
C_{\text {(graphite) }}+2 H_2(g) \rightarrow CH_4(g) \text { will be : }
$
The number of bent-shaped molecule/s from the following is $.....$. $N _3^{-}, NO _2^{-}, I _3^{-}, O _3, SO _2$
Which of the following is most reactive toward $S_{N^2}$ reaction ?
$H_2SeO_4 + NaOH \to  NaHSeO_4 ; E.W.$ of $H_2SeO_4 = E_1$
$H_2SeO_4 + 2NaOH \to  Na_2SeO_4 ; E.W.$ of $H_2SeO_4 = E_2$
Relation between $E_1$ and $E_2$
The solubility of $PbF_2$ (formula weight $= 245$) is $0.46\,g/L$. What is the solubility product
The oxidation states of iron atoms in compounds $(A),$ $(B)$ and $(C),$ respectively, are $x,$ $y$ and $z.$ The sum of $x, y$ and $z$ is........

$(A)$ $\left. Na _{4}\left[ Fe ( CN )_{5} NOS \right)\right]$

$(B)$ $Na _{4}\left[ FeO _{4}\right]$

$(C)$ $\left[ Fe _{2}( CO )_{9}\right]$

Given below are two statements, one is labelled as Assertion $A$ and the other is labelled as Reason $R$

Assertion $A :$- Carbon forms two important oxides $- CO$ and $CO _2 . CO$ is neutral whereas $CO _2$ is acidic in nature.

Reason $R :$- $CO _2$ can combine with water in a limited way to form carbonic acid, while $CO$ is sparingly soluble in water.

In the light of the above statements, choose the most appropriate answer from the options given below :-