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Exponents — Maths STD 8 — Question

Maharashtra BoardEnglish MediumSTD 8MathsExponents2 Marks
Question
Evaluate:
$\bigg\{\Big(\frac{-2}{3}\Big)^2\bigg\}^{-2}$
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Answer

$\bigg\{\Big(\frac{-2}{3}\Big)^2\bigg\}^{-2}$$=\Big(\frac{-2}{3}\Big)^{2\times(-2)}$
$=\Big(\frac{-2}{3}\Big)^{-4}$
$=\Big(\frac{-3}{2}\Big)^{4}$ $=\frac{(-3)\times(-3)\times(-3)\times(-3)}{2\times2\times2\times2}$ $=\frac{81}{16}$

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