MCQ
Evaluate: $ \displaystyle \underset{\text{x}\rightarrow 2}{\lim} \text{x}^2-5\text{x}+6$
- A1
- B-5
- C0
- D4
Solution:
$ = \displaystyle \underset{\text{x}\rightarrow 2}{\lim} \text{x}^2-5\text{x}+6$
$ ={ 2 }^{ 2 }-5\times 2+6$
= 4 - 10 + 6
= 0
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