Evaluate: _ x 2 x^2-4 x+3 : - Vidyadip

MCQ

Evaluate:$ \displaystyle\lim_{\text{x}\rightarrow 2} \dfrac{\text{x}^2-4}{\text{x}+3}:$

A
0
B
1
C
-1
D
None of these

✓

Answer

0

Solution:

Using direct substitution, we obtain,$ =\displaystyle\lim_{\text{x}\rightarrow 2} \dfrac{\text{x}^2-4}{\text{x}+3}$

$ =\dfrac{4-4}{2+3}=0$

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