MCQ
Evaluate $\left|\begin{array}{cc}x & x+1 \\ x-1 & x\end{array}\right|$
- A$0$
- ✓$1$
- C$2$
- D$3$
$\left|\begin{array}{cc}x & x+1 \\ x-1 & x\end{array}\right|=x(x)-(x+1)(x-1)=x^{2}-\left(x^{2}-1\right)=x^{2}-x^{2}+1=1$
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$\int\limits_0^2 {(t - {{\log }_2}a)\,dt} $ $= log_2$ $\left( {\frac{4}{{{a^2}}}} \right)$ is
| Column A | Column B |
| Maximum of Z | 325 |