Question
Evaluate the definite integral $\int _ { 2 } ^ { 3 } \frac { 1 } { x } d x.$

Answer

According to the question , $I =\int _ { 2 } ^ { 3 } \frac { 1 } { x } d x$
$ = [ \log | x | ] _ { 2 } ^ { 3 }$
$ = \log 3 - \log 2 $
$= \log \frac { 3 } { 2 }\left[ \because \log m - \log n = \log \frac { m } { n } \right]$

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