Question
Evaluate the definite integral $\int_{4}^{5} e^{x} d x$

Answer

Let $I=\int_{4}^{5} e^{x} d x$
$\Rightarrow I=\left[e^{x}\right]_{4}^{5}=e^{5}-e^{4}$
$\therefore \int_{4}^{5} \mathrm{e}^{\mathrm{x}} \mathrm{d} \mathrm{x}=\mathrm{e}^{4}(\mathrm{e}-1)$

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