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Permutations — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsPermutations2 Marks
Question
Evaluate the following:
$^8\text{P}_3$
✓

Answer

We have,
$^8\text{P}_3 = \frac{8!}{(8-3)!}\Big[\because\ ^\text{n}\text{P}_\text{r}=\frac{\text{n!}}{(\text{n}-\text{r})!}\Big]$
$= \frac{8\times7\times6\times5}{5!}$
$= 336$
Hence, $^8\text{P}_3= 336$

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