Question
Evaluate the following$: \frac{\sin 62^{\circ}}{\cos 28^{\circ}}$
✓
Answer
$ \frac{\sin 62^{\circ}}{\cos 28^{\circ}}$
$ =\frac{\sin \left(90^{\circ}-28^{\circ}\right)}{\cos 28^{\circ}}$
$ =\frac{\cos 28^{\circ}}{\cos 28^{\circ}}$
$ =1 .$
$ =\frac{\sin \left(90^{\circ}-28^{\circ}\right)}{\cos 28^{\circ}}$
$ =\frac{\cos 28^{\circ}}{\cos 28^{\circ}}$
$ =1 .$
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