Question
Evaluate the following integrals:$\int\limits^{\text{e}^2}_\text{e}\frac{1}{\text{x}\log\text{x}}\text{ dx}$
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Question is modified
If $|\mathrm{x}|<1$, then prove that $2 \tan ^{-1} \mathrm{x}=\tan ^{-1}\left(\frac{2 x}{1-x^2}\right)=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)=\cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right)$
| $X =x$ | $1$ | $2$ | $3$ |
| $P ( X =x)$ | $\frac{1}{5}$ | $\frac{2}{5}$ | $\frac{2}{5}$ |
$\cos \left(\frac{d y}{d x}\right)=a, a \in R, y(0)=2$