Question
Evaluate the following limit:
$\lim\limits_{\text{x}\rightarrow{\frac{\pi}{4}}}\frac{1-\tan\text{x}}{\text{x}-\frac{\pi}{4}}$

Answer

$\lim\limits_{\text{x}\rightarrow{\frac{\pi}{4}}}\frac{1-\tan\text{x}}{\text{x}-\frac{\pi}{4}}$
If $\text{x}\rightarrow\frac{\pi}{4},$ then $\text{x}-\frac\pi4\rightarrow0$
Let $\text{x}-\frac\pi4=\text{y}\Rightarrow\text{y}\rightarrow0$
$=\lim\limits_{\text{y}\rightarrow{0}}\frac{1-\tan\big(\text{y}+\frac{\pi}{4}\big)}{\text{y}}$
$=\lim\limits_{\text{y}\rightarrow{0}}\frac{1-\Bigg(\frac{\tan\text{y}+\tan\frac{\pi}{4}}{1-\tan\text{y}\tan\frac{\pi}{4}}\Bigg)}{\text{y}}$
$=\lim\limits_{\text{y}\rightarrow{0}}\frac{(1-\tan\text{y}-\tan\text{y}-1)}{\text{y}(1-\tan\text{y})}$ $\Big[\because\tan\frac{\pi}{4}=1\Big]$
$=\lim\limits_{\text{y}\rightarrow{0}}\frac{(-2\tan\text{y})}{(1-\tan\text{y})}$
$=-2\lim\limits_{\text{y}\rightarrow{0}}\frac{\tan\text{y}}{\text{y}}\times\frac{1}{\lim\limits_{\text{y}\rightarrow{0}}(1-\tan\text{y})}$
$=-2\times1\frac{1}{(1-0)}$ $\Big[\because\lim\limits_{\theta\rightarrow{0}}\frac{\sin\theta}{\theta}=1\Big]$
$=-2$

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