Question
Evaluate the following:
$\sin^{-1}(\sin12)$

Answer

We know $\sin\big(\sin^{-1}\theta\big)=\theta$ if $-\frac{\pi}{2}\leq\theta\leq\frac{\pi}{2}$We have
$\sin^{-1}(\sin12)=\sin^{-1}\{\sin(-\pi+12)\}$ $=12-\pi$

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