Question
Evaluate the following$: \sin22^\circ \cos44^\circ - \sin46^\circ \cos68^\circ $
✓
Answer
$\sin22^\circ \cos44^\circ - \sin46^\circ \cos68^\circ $
$= \sin(90^\circ - 68^\circ ) \cos(90^\circ - 46^\circ ) - \sin46^\circ \cos68^\circ $
$= \cos68^\circ \sin 46^\circ - \sin46^\circ \cos68^\circ $
$= 0.$
$= \sin(90^\circ - 68^\circ ) \cos(90^\circ - 46^\circ ) - \sin46^\circ \cos68^\circ $
$= \cos68^\circ \sin 46^\circ - \sin46^\circ \cos68^\circ $
$= 0.$
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