Question
Evaluate : $\frac{-4}{9}-\frac{2}{-3}$

Answer

$3$ $9, 3$
$5$ $3, 1$
  $1, 1$
$=\frac{-4 \times 1}{9 \times 1}-\frac{-2 \times 3}{3 \times 3}$
$(\text{LCM}$ of $3$ and $9=9)$
$\frac{-4+6}{9}=\frac{2}{9}$

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