Question
Evaluate:

$\int \frac{\sin x}{\cos ^2 x} \cdot d x$

Answer

$\begin{aligned} \int \frac{\sin x}{\cos ^2 x} d x & =\int\left(\frac{1}{\cos x}\right)\left(\frac{\sin x}{\cos x}\right) d x \\ & =\int \sec x \tan x d x \\ & =\sec x+c .\end{aligned}$

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