Question
Expand using suitable identity: $(-2x + 3y + 2z)^2$

Answer

$(- 2x + 3y + 2z)^2$
$= {(-2x) + 3y + (2z)}^2$
$= (-2x)^2 + (3y)^2 + (2z)^2 + 2(-2x)(3y) + 2(3y)(2z) + 2(2z)(-2x)$
$($Using Identity$ (a + b + c)^2= a^2+ b^2+ c^2+ 2ab + 2bc + 2ca)$
$= 4x^2 + 9y^2 + 4z^2 - 12xy+ 12yz - 8zx$

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