Question
Expand using suitable identity: $(x + 2y + 4z)^2$

Answer

$(x + 2y + 4z)^2$
$= (x)^2 + (2y)^2 + (4z)^2 + 2(x)(2y) + 2(2y)(4z) + 2(4z)(x)$
$($Using Identity $(a + b + c)^2= a^2+ b^2+ c^2+ 2ab + 2bc + 2ca)$
$= x^2 + 4y^2+ 16z^2 + 4xy + 16yz + 8zx$

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