Question
Explain ambidentate ligand with example.
✓
Answer
⇒ Ligands that can attach themselves to the central metal atom through two different atoms are called ambidentate ligands.
⇒ Examples of such ligands are the NO-2 and SCN- ions. NO-2 ion can coordinate either through nitrogen or through oxygen to a central metal atom/ion.
⇒ Similarly, SCN- ion can coordinate through the sulphur or nitrogen atom.
⇒ Examples of such ligands are the NO-2 and SCN- ions. NO-2 ion can coordinate either through nitrogen or through oxygen to a central metal atom/ion.
⇒ Similarly, SCN- ion can coordinate through the sulphur or nitrogen atom.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
0.05 moles of ethanoic acid is dissolved in $2 5 0 ~ g m$ benzene. Calculate molality of solution.
→How is the variability in oxidation states of transition metals different from that of the non transition metals? Illustrate with examples.
State the characteristics of Interstitial compounds.
Some halogen containing compounds are useful in daily life. Some compounds of this class are responsible for exposure of flora and fauna to more and more of UV light which causes destruction to a great extent. Name the class of these halocompounds. In your opinion, what should be done to minimise harmful effects of these compounds.
State Kohlrausch law of independent migration of ions. Why does the conductivity of a solution decrease with dilution?
Compare the general characteristics of the first series of the transition metals with those of the second and third series metals in the respective vertical columns. Give special emphasis on the following points:
Oxidation states
Oxidation states
Arrange the following in the decreasing order of their acidic character.
- C6H5COOH, FCH2COOH, NO2CH2COOH
- CH3CH2OH, CH3COOH, ClCH2COOH, FCH2COOH, C6H5CH2COOH
State the importance of diazonium salts in the synthesis of aromatic compounds.
An organic compound with the molecular formula C9H10O forms 2,4-DNP derivative, reduces Tollens’ reagent and undergoes Cannizzaro reaction. On vigorous oxidation, it gives 1, 2-benzenedicarboxylic acid. Identify the compound.