Question
Explain the following:
$CO_2$ is a better reducing agent below $710K$ whereas $CO$ is a better reducing agent above $710K.$
$CO_2$ is a better reducing agent below $710K$ whereas $CO$ is a better reducing agent above $710K.$
✓
Answer
According to Ellingham diagram, at temperature below $710K,$
$\triangle\text{G}^{0}_{(\text{C, CO}_{2})} < \triangle\text{G}^{0}_{(\text{C, CO})}$
Hence $CO_2$ is better reducing agent. At above $710K,$ $\triangle\text{G}^{0}_{(\text{C, CO}_{2})} < \triangle\text{G}^{0}_{(\text{C, CO})}$ Hence, $CO$ is brtter agent.
$\triangle\text{G}^{0}_{(\text{C, CO}_{2})} < \triangle\text{G}^{0}_{(\text{C, CO})}$
Hence $CO_2$ is better reducing agent. At above $710K,$ $\triangle\text{G}^{0}_{(\text{C, CO}_{2})} < \triangle\text{G}^{0}_{(\text{C, CO})}$ Hence, $CO$ is brtter agent.
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