Question
Explain the Heisenberg's uncertainity principle.

Answer

SELF

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Following cell is set up between copper and silver electrodes.

$\text{Cu}|\text{Cu}^{2+}\text{(aq)}\|\text{Ag}^+\text{(aq)}|\text{Ag}$

If its two half cells work under standard conditions, calculate the emf of the cell.

$\Big[\text{Given E}^\circ_{\frac{\text{Cu}^{2+}}{\text{Cu}}}=+0.34\text{V},\text{E}^\circ_{\frac{\text{Ag}^+}{\text{Ag}}}=+0.80\text{V}\Big]$

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