Question
Explain the procedure to determine the density of an unknown liquid using a relative density bottle.
✓
Answer
The density of an unknown liquid can be determined using a relative density bottle as follows.
Step $1$ : Wash the $\text{RD}$ bottle with distilled water. Dry it well.
Step $2$ : Insert the stopper and find its mass using the balance. Note down the mass of the empty $\text{RD}$ bottle.
Step $3$ : Fill the bottle with distilled water. Insert the stopper. Some water will drain out through the stopper. Dry the bottle well from outside.
Step $4$ : Find the mass of the bottle filled with distilled water.
Step $5$ : Empty the bottle and dry it well. Fill it with the liquid whose relative density is to be determined and insert the stopper. Some liquid will drain out through the stopper. Dry the bottle well from outside. Find the mass of the bottle filled with liquid.
Step $6$ : Do the calculations as follows.
Mass of the empty bottle $= m1$
Mass of bottle $+$ distilled water $= m2$
Mass of bottle $+$ liquid $= m3$
Mass of distilled water $– (m2 – m1)$
Relative density of the liquid $=\frac{m_3-m_1}{m_2-m_1}$
Mass of liquid $= (m3 – m1)$
As volume of both the liquid and water are the same,
Density of the liquid $=\frac{m_3-m_1}{m_2-m_1} \times 1 g / cm ^3$
Step $1$ : Wash the $\text{RD}$ bottle with distilled water. Dry it well.
Step $2$ : Insert the stopper and find its mass using the balance. Note down the mass of the empty $\text{RD}$ bottle.
Step $3$ : Fill the bottle with distilled water. Insert the stopper. Some water will drain out through the stopper. Dry the bottle well from outside.
Step $4$ : Find the mass of the bottle filled with distilled water.
Step $5$ : Empty the bottle and dry it well. Fill it with the liquid whose relative density is to be determined and insert the stopper. Some liquid will drain out through the stopper. Dry the bottle well from outside. Find the mass of the bottle filled with liquid.
Step $6$ : Do the calculations as follows.
Mass of the empty bottle $= m1$
Mass of bottle $+$ distilled water $= m2$
Mass of bottle $+$ liquid $= m3$
Mass of distilled water $– (m2 – m1)$
Relative density of the liquid $=\frac{m_3-m_1}{m_2-m_1}$
Mass of liquid $= (m3 – m1)$
As volume of both the liquid and water are the same,
Density of the liquid $=\frac{m_3-m_1}{m_2-m_1} \times 1 g / cm ^3$
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Match the following :
→| Column $A$ | Column $B$ | ||
| $(a)$ | $kg m^-3$ | $(i)$ | relative density |
| $(b)$ | no unit | $(ii)$ | sinks in alcohol |
| $(c)$ | relative density | $(iii)$ | floats on water |
| $(d)$ | iron | $(iv)$ | density |
| $(e)$ | wood | $(v)$ | density bottle |
Figure below shows a metal rod $AB$ placed on an insulating stand. In figure $(a)$ a negatively charged ebonite rod $C$ is touched with the metal rod $AB$, while in figure $(b)$, the negatively charged ebonite rod $C$ is held near the rod $AB$. State the kind of charges at the ends $A$ and $B$ of the rod, in each case.
→Match the Following$>$
→| Column $A$ | Column $B$ |
| $(a)$ white Light | $(1)$ Convex mirror |
| $(b)$ Refraction | $(2)$ Concave mirror |
| $(c)$ Virtual images | $(3)$ refraction |
| $(d)$ Real images | $(4)$ spectrum |
| $(e)$ Prism | $(5)$ ray of light from glass to air |