Question
Explain the shape of $BrF_5$.
✓
Answer
Br-atom has configuration:
$1s^2, 2s^22p^6 , 3s^23p^63d^{10}, 4s^24p^5$
To get pentavalency, two of the p-orbitals are unpaired and electrons are shifted to 4d-orbitals.
In this excited state, $sp^3d^2$ hybridisation occurs giving octahedral structure. Five positions are occupied by $F$ atoms forming sigma bonds with hybrid bonds and one position occupied by lone pair, i.e., the molecule as a square pyramidal shape.
$1s^2, 2s^22p^6 , 3s^23p^63d^{10}, 4s^24p^5$
To get pentavalency, two of the p-orbitals are unpaired and electrons are shifted to 4d-orbitals.
In this excited state, $sp^3d^2$ hybridisation occurs giving octahedral structure. Five positions are occupied by $F$ atoms forming sigma bonds with hybrid bonds and one position occupied by lone pair, i.e., the molecule as a square pyramidal shape.
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