Question
Explain the structure of triple bond.
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$\text{CCI}_4(\text{g})\xrightarrow{ \ \ \ \ \ }\text{C}(\text{g})+4\text{CI}(\text{g})$
and calculate bond enthalpy of C – Cl in CCl4(g).$\Delta_\text{vap}\text{H}^\ominus(\text{CCI}_4)=30.5\text{kJ} \ \text{mol}^{-1}.$
$\Delta_\text{f}\text{H}^\ominus(\text{CCI}_4)=-135.5\text{kJ} \ \text{mol}^{-1}.$
$\Delta_\text{a}\text{H}^\ominus(\text{C})=-715.0\text{kJ} \ \text{mol}^{-1},$ where $\Delta_\text{a}\text{H}^\ominus$ is enthalpy of atomisation
$\Delta_\text{a}\text{H}^\ominus(\text{CI}_2)=242\text{kJ} \ \text{mol}^{-1}$
$\text{N}_2\text{O}_4(\text{g}) +3\text{CO} (\text{g})\xrightarrow{ \ \ \ \ \ \ } \text{N}_2\text{O}(\text{g}) + 3\text{CO}_2(\text{g})$
H2O, NH3, NF3 and PCl5
XeF4 and SF4. (At. No. of Xe = 54, At. No. of S = 16)