Question
Explain the various reduction reactions of nitrobenzene.

Answer

Get the step-by-step solution for this question inside the Vidyadip app.

Get the answer in the app

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Sodium borohydride reacts with iodine in the presence of diglyme to give A. A heated at 388 K give B. A heated at 373 K in sealed tube to form C. A further heated at red hot condition to give element D. Find out A, B, C and D. Give the reactions.
An organic compound (A) of molecular formula $C _2 H _6 O$ liberates $H _2$ gas with metallic sodium and gives (B). (B) on reaction with methyl bromide produces (C) of molecular formula $C _3 H _8 O$. (C) on reaction with excess III produces ( D ) and ( E ). Identify $A , B , C , D$ and E and explain the reactions involved.
Explain the preparation of silicones.
Write a notes on
  1. Sheet silicates
  2. Three dimensional silicate
How does ammonia react with
1. Excess $Cl _2$
2. $Na$
3. $CuSO _4$
4. $O _2 / \Delta$
Explain briefly the collision theory of bimolecular reactions.
 An organic compound $(A)$ of molecular formula $C _7 H _8 O$ on oxidation with alkaline $KMnO _4$ gives $(B)$ of formula $C _7 H _6 O$. (B) on reaction with $Cl _2$ in the presence of catalyst $FeCl _3$ gives (C) of formula $C _7 HOCl$. (B) on reaction with $Cl _2$ in the absence of catalyst gives $C _7 H _5 OCl$. Identify $A , B , C , D$ and explain the reaction involved.
Give reasons for each of the following :
  1. Bleaching of flowers by $Cl_2$ is permanent while by $SO_2$ is temporary.
  2. Molten aluminium bromide is a poor conductor of electricity.
  3. Nitric oxide becomes brown when released in air.
  4. $PCl_5$ is ionic in nature in the solid-state.
  5. Ammonia is a good complexing agent.
How do nature of the reactant influence rate of reaction?
An organic compound (A) of molecular formula $C _7 H _8$ on reaction with hot alkaline $KMnO _4$ gives (B) of formula $C _7 H _6 O _2$ which gives brisk effervescence with $NaHCO _3$ solution. (B) on reaction with sodium hydroxide gives (C) of formula $C _7 H _5 O _2 Na$. Compound (C) on treatment with sodalime gives (D) the simplest aromatic hydrocarbon.