MCQ
Exponential form of $\Big(\sqrt{\sqrt{\text{a}}\times\sqrt{\text{b}}}\Big)^2$ is:
- A$\text{ab}$
- ✓$(\text{ab})^{\frac{1}{2}}$
- C$(\text{ab})^{\frac{1}{4}}$
- D$(\text{ab})^2$
Consider $\Big(\sqrt{\sqrt{\text{a}}\times\sqrt{\text{b}}}\Big)^2$ and simplify it as follows:
$\Big(\sqrt{\sqrt{\text{a}}\times\sqrt{\text{b}}}\Big)^2=(\sqrt{\text{a}}\times\sqrt{\text{b}})^{\frac{1}{2}\times2}$
$=\sqrt{\text{ab}}=(\text{ab})^{\frac{1}{2}}$
Hence, $\Big(\sqrt{\sqrt{\text{a}}\times\sqrt{\text{b}}}\Big)^2=(\text{ab})^{\frac{1}{2}}.$
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