Question
Express in terms of $\log 2$ and $\log 3:\log 144$

Answer

$\log 144= \log( 2 \times 2 \times 2 \times 2 \times 3 \times 3 )$
$= \log( 2^4 \times 3^2 )$
$= \log( 2^4 ) + \log( 3^2 ) ....[ \log_amn = \log_am + \log_an]$
$= 4 \log2 + 2 \log3 ....[ \log_am^n = n \log_am ]$

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