Question
Express $N(16, 0.5)$ in the interval and modulus form.

Answer

$\mathrm{N}(16,0.5) \therefore a=16, \delta=0.5$
In Interval form: $(a-\delta, a+\delta)$
Putting $a=16 ; \delta=0.5$,
$N(16,0.5)=(16-0.5,16+0.5)$ $=(15.5,16.5)$
In Modulus form: $|x-a|<\delta$
Putting $a=16 ; \delta=0.5$,
$N(16,0.5)=|x-16|<0.5$

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