Question
Express the following as a sum or difference of two trigonometric functions : $2 \sin \frac{2 \pi}{3} \cos \frac{\pi}{2}$

Answer

$\begin{aligned}
2 \sin \frac{2 \pi}{3} \cos \frac{\pi}{2} & =\sin \left(\frac{2 \pi}{3}+\frac{\pi}{2}\right)+\sin \left(\frac{2 \pi}{3}-\frac{\pi}{2}\right) \\
& =\sin \frac{7 \pi}{6}+\sin \frac{\pi}{6}
\end{aligned}
$
[Note: Answer given in the textbook is $\sin \frac{7 \pi}{12}+\sin \frac{\pi}{12}$ However, as per our calculation it is $\sin \frac{7 \pi}{6}+\sin \frac{\pi}{6}$

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