Question
Express the following in exponential form: $1250$
✓
Answer
$1250$
$= 2 \times 5 \times 5 \times 5 \times 5 = 2 \times 5^4 $
| $2$ | $1250$ |
| $5$ | $625$ |
| $5$ | $125$ |
| $5$ | $25$ |
| $5$ | $5$ |
| $1$ |
$= 2 \times 5 \times 5 \times 5 \times 5 = 2 \times 5^4 $
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In the given figure, the directed lines are parallel to each other. Find the unknown angles.
Evaluate: $(5 m-2 n)(5 m+2 n)\left(25 m^2+4 n^2\right)$
→Out of 1200 pupils in a school, 900 are boys and the rest are girls. If 20% of the boys and 30% of the girls wear spectacles, find :
(i) how many pupils in all, wear spectacles?
(ii) what percent of the total number of pupils wear spectacles?
(i) how many pupils in all, wear spectacles?
(ii) what percent of the total number of pupils wear spectacles?
In the given figure, angle $A D B=90^{\circ}, A C=A B=26 cm$ and $B D=$ $D C$. If the length of $A D=24 cm$; find the length of $B C$.
→$A B, C D$ and $E F$ are three lines intersecting at the same point.
(i) Find $x$, if $y=45^{\circ}$ and $z=90^{\circ}$.
(ii) Find $a$, if $x=3 a, y=5 x$ and $r=6 x$.
→→(i) Find $x$, if $y=45^{\circ}$ and $z=90^{\circ}$.
(ii) Find $a$, if $x=3 a, y=5 x$ and $r=6 x$.
The inner circumference of a circular track is 264 m and the width of the track is 7 m. Find:
(i) the radius of the inner track.
(ii) the radius of the outer circumference.
(iii) the length of the outer circumference.
(iv) the cost of fencing the outer circumference at the rate of ₹50 per m.
(i) the radius of the inner track.
(ii) the radius of the outer circumference.
(iii) the length of the outer circumference.
(iv) the cost of fencing the outer circumference at the rate of ₹50 per m.
Simplify and express the Solution in the positive exponent form:
$\frac{36 \times(-6)^2 \times 3^6}{12^3 \times 3^5}$
→$\frac{36 \times(-6)^2 \times 3^6}{12^3 \times 3^5}$
Evaluate: $(a+1)\left(a^2-a+1\right)$ and $(a-1)\left(a^2+a+1\right)$
→125 pupils have food sufficient for 18 days. If 25 more pupils join them, how long will the food last now? What assumption have you made to come to your answer?