MCQ
Extra pure $\mathrm{N}_2$ can be oblained by heating
- A$\mathrm{NH}_3$ with $\mathrm{CuO}$
- B$\mathrm{NH}_4 \mathrm{NO}_3$
- C$\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$
- ✓$\mathrm{Ba}\left(\mathrm{N}_3\right)_2$
$2 NaN _3 \xrightarrow{573 K} 2 Na +3 N_2$
Azide salt of barium can be obtained in the purest form as well as the decomposition product contains solid Ba as a by-product along with gaseous nitrogen, hence no additional step of separation is required.
$Ba \left( N _3\right)_2 \xrightarrow{\text { heat }} Ba +3 N_2$
Hence, option $D$ is correct.
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Statement $I:$ Iron $(III)$ catalyst, acidified $K _{2} Cr _{2} O _{7}$ and neutral $KMnO _{4}$ have the ability to oxidise $I$ to $I _{2}$ independently.
Statement $II$: Manganate ion is paramagnetic in nature and involves $p \pi- p \pi$ bonding.
In the light of the above statements, choose the correct answer from the options.
$(i)$ A $0.5\,m$ $NaBr$ solution has a higher vapour pressure than a $0.5\,m\,BaCl_2$ solution at the same temperature
$(ii)$ Pure water freezes at the higher temperature than pure methanol
$(iii)$ a $0.1\,m\,NaOH$ solution freezes at a lower temperature than pure water
Choose the correct answer from the codes given below
$(I)$ $BO_3^{-3} > CO_3^{-2} > NO_3^-$
$(II)$ $ClO_4^-> SO_4^{-2} > PO_4^{-3}$
$(III)$ $BF_3 > BCl_3 > BBr_3$
$(IV)$ $AlCl_3 > BCl_3$