Question
Factorise: $1 - 25 (a+ b)^2$

Answer

$1 - 25 (a+ b)^2$
$= (1)^2 - [5(a+b)]^2$
$= [1 + 5(a+b)] [1 - 5(a+b)]$
$= (1 + 5a + 5b) (1 - 5a - 5b)$

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