Question
Factorise : $3a^2b - 12a^2 - 9b + 36$
✓
Answer
$3a^2b - 12a^2 - 9b + 36$
$= 3a^2 (b - 4) - 9 (b - 4)$
$= (b - 4) (3a^2- 9)$
$= (b - 4) 3 (a^2 - 3)$
$= 3 (b - 4) (a^2-3)$
$= 3a^2 (b - 4) - 9 (b - 4)$
$= (b - 4) (3a^2- 9)$
$= (b - 4) 3 (a^2 - 3)$
$= 3 (b - 4) (a^2-3)$
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