Question
Factorise : $6a^2 - 3a^2b - bc^2 + 2c^2$

Answer

$6a^2 - 3a^2b - bc^2 + 2c^{2}$
$= 6a^2 - 3a^2b + 2c^2 - bc^2$
$= 3a^2 (2 - b) + c^2 (2 - b)$
$= (2 - b) (3a^2 + c^2)$

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